A girl standing on a pedstal at rest throws a ball upwards with maximum possible speed of 50 ms -1 . If the platform starts moving up at 5 ms -1 and the girl again throws the similar ball in similar way. The time taken in the previous case and the lime taken in the second case to return to her hands are
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Time taken to reach the highest point,
t = u/g = 50/10 = 5s
Total time taken to reach back = 5 + 5 = 10s
When platform starts moving with uniform speed, the acceleration is nil. Motion of the ball and the girl w.r.t. each other is unaffected so total time taken in this case also is 10s.
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